document.write( "Question 448928: Convert each equation to the standard form of conic section
\n" ); document.write( "y^2+6y-x=0
\n" ); document.write( "x^2-y^2-6x+13=0
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Algebra.Com's Answer #308820 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Converting each equation to the standard form of conic section
\n" ); document.write( "y^2+6y-x=0 |Parabola opening right or left
\n" ); document.write( " x = y^2+6y
\n" ); document.write( " x = (y+3)^2 - 9 |Vertex form V(-9,-3)
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\n" ); document.write( "x^2-y^2-6x+13=0 |Hyperbola opening up and down (multiplying thru by -1)
\n" ); document.write( " y^2 - x^2 + 6x -13 = 0
\n" ); document.write( " y^2 -[(x-3)^2 -9] - 13 = 0
\n" ); document.write( " y^2 -(x-3)^2 +9 - 13 = 0
\n" ); document.write( " y^2 - (x-3)^2 = 4
\n" ); document.write( "\"y%5E2%2F4+-+%28x-3%29%5E2%2F4+=+1\"\r
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