document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448715>Question 448715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wheel has a radius of 3 feet. As the wheel turns, a rope connected to a five kilogram weight winds onto the wheel, causing the weight to move. If the wheel turns 135 degrees, to the nearest food, how far does the weight move? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308813 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A wheel has a radius of 3 feet. As the wheel turns, a rope connected to a five kilogram weight winds onto the wheel, causing the weight to move. If the wheel turns 135 degrees, to the nearest food, how far does the weight move<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Circumference of the wheel=2&#960;*radius=6&#960; feet<BR>\n" );
document.write( "For each revolution or 360º turn of the wheel, the 5 kg weight will move 6&#960; feet<BR>\n" );
document.write( "so, for a 135º turn the 5 kg weight will move (135/360)*6&#960;=7.07 ft  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );