document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448889>Question 448889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the following identity: tan(x+pie/4)=1+tanx/1-tanx </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308810 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve the following identity: tan(x+pie/4)=1+tanx/1-tanx<BR>\n" );
document.write( "..<BR>\n" );
document.write( "tan(x+pie/4)=1+tanx/1-tanx<BR>\n" );
document.write( "start from the left side<BR>\n" );
document.write( "using addition formula for tan: tan(s+t)=(tan s+tan t)/(1-tan s tan t)<BR>\n" );
document.write( "tan &#960;/4=1<BR>\n" );
document.write( "tan(x+&#960;/4)=(tan x+tan &#960;/4)/(1-tan x tan &#960;/4)<BR>\n" );
document.write( "                  =tan x+1/1-tan x<BR>\n" );
document.write( "                  =1+tanx/1-tanx<BR>\n" );
document.write( "ans: left side=right side </SPAN>\n" );
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