document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448800>Question 448800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bicycler traveling 12 mph passes a runner traveling 9 mph.  If the runner started at noon, and the bicycler at 12:30, how far from the start point did they meet?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308771 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> runner	9	mph					<BR>\n" );
document.write( "bicycler	12	mph					<BR>\n" );
document.write( "runner		12:00					<BR>\n" );
document.write( "bicycler		12:30					<BR>\n" );
document.write( "Difference in time=		00:30	0.5				<BR>\n" );
document.write( "Runner will have covered 		4.5	miles	before 	bicycler		starts<BR>\n" );
document.write( "catch up distance=		4.5	miles				<BR>\n" );
document.write( "catch up speed =		12	-9	mph			<BR>\n" );
document.write( "catch up speed =		3	mph				<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed							<BR>\n" );
document.write( "catch up time=		4.5	/	3			<BR>\n" );
document.write( "catch up time=		1.5	hours<BR>\n" );
document.write( "bicycler speed = 12 mph<BR>\n" );
document.write( "time = 1.5				<BR>\n" );
document.write( "12*1.5= 18 miles </SPAN>\n" );
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