document.write( "Question 46591: Let f(x) =2x^2 + x-1 . Sketch the graph of on the set of axes and find each of the following.\r
\n" ); document.write( "\n" ); document.write( " Vertex: \r
\n" ); document.write( "\n" ); document.write( " x-intercept(s): \r
\n" ); document.write( "\n" ); document.write( " y-intercept(s): \r
\n" ); document.write( "\n" ); document.write( " Axis of symmetry:
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Algebra.Com's Answer #30871 by Nate(3500)\"\" \"About 
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f(x) = 2x^2 + x - 1
\n" ); document.write( "vertex(-b/2a,f(x))
\n" ); document.write( "v(-1/4,-9/8)
\n" ); document.write( "x-intercept:
\n" ); document.write( "0 = 2x^2 + x - 1
\n" ); document.write( "1 = 2x^2 + x
\n" ); document.write( "1/2 = x^2 + (1/2)x
\n" ); document.write( "8/16 + 1/16 = (x + (1/4))^2
\n" ); document.write( "+- sqrt(9/16) = x + 1/4
\n" ); document.write( "-1/4 +- 3/4 = x
\n" ); document.write( "(-1,0) and (1/2,0)
\n" ); document.write( "y-intercept:
\n" ); document.write( "f(x) = 2x^2 + x - 1 = 2(0)^2 + 0 - 1 = -1
\n" ); document.write( "(0,-1)
\n" ); document.write( "Axis of Symmetry:
\n" ); document.write( "Since the parabola is vertical, the axis of symmetry is valued as 'x'. \"x+=+-1%2F4\"
\n" ); document.write( "\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C2x%5E2%2Bx-1%29\" \n" ); document.write( "
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