document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448516>Question 448516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sin(Arccos(-2/5)\r<BR>\n" );
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document.write( "I need help finding the wrapping function of (-2/5) I am not quite sure on how to find the denominator of 5. Our teacher only taught us 2,3,4,6,8, and 12. Thank you for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308704 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin(Arccos(-2/5))<BR>\n" );
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document.write( "The point is on a circle of radius 5, and the x value is -2<BR>\n" );
document.write( "It's the 2nd quadrant (the principal value).<BR>\n" );
document.write( "Find the y value.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2+=+5%5E2+-+2%5E2+=+21 ALIGN=MIDDLE  ALT=\"y%5E2+=+5%5E2+-+2%5E2+=+21\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y = sqrt(21)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sine+=+sqrt%2821%29%2F5 ALIGN=MIDDLE  ALT=\"sine+=+sqrt%2821%29%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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