document.write( "Question 5881: what does the inequality 2x-4y>-6 look like on a graph? \n" ); document.write( "
Algebra.Com's Answer #3087 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
first find what 2x-4y=-6 looks like, since this will be a straight line you can plot/sketch. Then 2x-4y>-6 will be either the region above the line or the region below the line.\r
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\n" ); document.write( "\n" ); document.write( "So, to stech the line, we need it in the form y=mx+c, so:\r
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\n" ); document.write( "\n" ); document.write( "2x-4y=-6
\n" ); document.write( "-4y=-2x-6 or...
\n" ); document.write( "4y = 2x+6
\n" ); document.write( "y = (2/4)x + 6/4
\n" ); document.write( "--> y = (1/2)x + 3/2\r
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\n" ); document.write( "\n" ); document.write( "so, we know the gradient is +1/2
\n" ); document.write( "and we know the line crosses the y-axis at y=3/2.\r
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\n" ); document.write( "\n" ); document.write( "So, sketch that.\r
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\n" ); document.write( "\n" ); document.write( "Now for your question...where is 2x-4y>-6? well, following through the same process:\r
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\n" ); document.write( "\n" ); document.write( "2x-4y > -6
\n" ); document.write( "-4y > -2x-6 or...
\n" ); document.write( "4y < 2x+6 -- since we multiplied all terms by -1 (to swap all signs round) we swap the > into a <
\n" ); document.write( "y < (2/4)x + 6/4
\n" ); document.write( "--> y < (1/2)x + 3/2\r
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\n" ); document.write( "\n" ); document.write( "so, where is y less than the straight line? Answer: below the line.\r
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\n" ); document.write( "\n" ); document.write( "So we want the region below the line.\r
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\n" ); document.write( "\n" ); document.write( "Jon.\r
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