document.write( "Question 448352: can you please help me solve this trigonometric equation:\r
\n" ); document.write( "\n" ); document.write( "2sin^2x-cosx-1=0
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Algebra.Com's Answer #308649 by lwsshak3(11628)\"\" \"About 
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can you please help me solve this trigonometric equation:
\n" ); document.write( "2sin^2x-cosx-1=0
\n" ); document.write( "..
\n" ); document.write( "for 0\n" ); document.write( "2sin^2x-cosx-1=0
\n" ); document.write( "2(1-cos^2x)-cosx-1=0
\n" ); document.write( "2-2cos^2x-cosx-1=0
\n" ); document.write( "-2cos^2x-cosx+1=0
\n" ); document.write( "2cos^2x+cosx-1=0
\n" ); document.write( "(2cosx-1)(cosx+1)=0
\n" ); document.write( "2cosx-1=0
\n" ); document.write( "cosx=1/2
\n" ); document.write( "x=π/3,5π/3
\n" ); document.write( "..
\n" ); document.write( "cosx+1=0
\n" ); document.write( "cosx=-1
\n" ); document.write( "x=π
\n" ); document.write( "..
\n" ); document.write( "ans:
\n" ); document.write( "x=π, π/3, 5π/3
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