document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448389>Question 448389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an isotope of Strontium 90 has a half life of 38 years. if you have 500mg of this isotope today how many milligrams will you have in 19 years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308627 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> an isotope of Strontium 90 has a half life of 38 years.<BR>\n" );
document.write( " if you have 500mg of this isotope today how many milligrams will you have in 19 years.<BR>\n" );
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document.write( "The radioactive decay formula:<BR>\n" );
document.write( "A = Ao*2(-t/h), where:<BR>\n" );
document.write( "A = amt after t yrs<BR>\n" );
document.write( "Ao = initial amt<BR>\n" );
document.write( "t = time<BR>\n" );
document.write( "h = half-life of substance<BR>\n" );
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document.write( "A = 500*2(-19/38)<BR>\n" );
document.write( "A = 500*2(-1/2}<BR>\n" );
document.write( "A = 500 * .7071<BR>\n" );
document.write( "A = 353.55 milligrams after 19 yrs<BR>\n" );
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document.write( " </SPAN>\n" );
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