document.write( "Question 448400: solve 2sin^2x- square root of 3 sinx=0 \n" ); document.write( "
Algebra.Com's Answer #308569 by Gogonati(855)\"\" \"About 
You can put this solution on YOUR website!
\"2%28sinx%29%5E2-sqrt%283%29%2Asinx=0\", assuming sinx≠0 or x≠n*\"pi\",\r
\n" ); document.write( "\n" ); document.write( "divide both sides by sinx and get:\"2sinx=sqrt%283%29\"=>\"sinx=sqrt%283%29%2F2\", \r
\n" ); document.write( "\n" ); document.write( "where its solution is:\"x=2n%2Api%2B%28pi%29%2F3\" and \"x=2n%2Api%2B2%2Api%2F3\".
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