document.write( "Question 448359: The sum of the digits of a two digit numeral is 11. If the digits were reversed, the resulting number would be 45 greater than the original number. What is the original numeral? \n" ); document.write( "
Algebra.Com's Answer #308508 by rwm(914)\"\" \"About 
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a+b=11
\n" ); document.write( "10a+b-10b-a=45
\n" ); document.write( "9a-9b=45
\n" ); document.write( "a-b=5
\n" ); document.write( "a+b=11
\n" ); document.write( "2a=16
\n" ); document.write( "a=8
\n" ); document.write( "b=3
\n" ); document.write( "check
\n" ); document.write( "83-38=45
\n" ); document.write( "ok
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