document.write( "Question 448353: the length and width of a rectangle are 6 m and 4 m. when eacch dimension is increased by the same amount, the area of the new rectangle is 50. find the dimensions of the new rectangle \n" ); document.write( "

Algebra.Com's Answer #308503 by mananth(16946) $\"\"$ $\"About$

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length =6
\n" ); document.write( "width = 4\r
\n" ); document.write( "\n" ); document.write( "increased by x
\n" ); document.write( "new length = 6+x
\n" ); document.write( "new width = 4+x
\n" ); document.write( "Area = (6+x)(4+x)
\n" ); document.write( "50 = 24+10x+x^2\r
\n" ); document.write( "\n" ); document.write( "x^2+10x-26=0
\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "a= 1 ,b= 10 ,c= -26
\n" ); document.write( "
\n" ); document.write( "b^2-4ac=100 + 104
\n" ); document.write( "b^2-4ac=204
\n" ); document.write( " $\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( " $\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( " $\"x1=%28-12%2Bsqrt%2824%29%29%2F%2812%29\"$
\n" ); document.write( "x1=(-10 +14.28)/2
\n" ); document.write( "x1=2.14
\n" ); document.write( "x2=(-10 -14.28)/2
\n" ); document.write( "x2= -12.14
\n" ); document.write( "ignore negative value.
\n" ); document.write( "x= 2.14, add this to old length
\n" ); document.write( "new length = 8.14
\n" ); document.write( "new width = 6.14 \n" ); document.write( "

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