document.write( "Question 448333: 3) The units digit is 3 times more the tens digit. When the digits are reversed, the new number is 54 more than the original.\r
\n" ); document.write( "\n" ); document.write( "4)The units digit is 3 times the tens digit. The number is 12 more than 9 times the tens digit.\r
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\n" ); document.write( "\n" ); document.write( "(WILL GIVE AMAZING COMMENT.)
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Algebra.Com's Answer #308492 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started. If you need more help, then repost. \r
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\n" ); document.write( "\n" ); document.write( "# 3\r
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\n" ); document.write( "\n" ); document.write( "Let u = units digit and t = tens digit\r
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\n" ); document.write( "\n" ); document.write( "So the original number is then \"10t%2Bu\". The reversed digit number is \"10u%2Bt\" (swap u and t). Ex: if t = 5 and u = 9, then the original number is 59 and the swapped number is 95. \r
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\n" ); document.write( "\n" ); document.write( "Since \"The units digit is 3 times more the tens digit\", we know that \"u=3t\" (ie multiply the tens digit t by 3 to get the units digit u).\r
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\n" ); document.write( "\n" ); document.write( "Now \"When the digits are reversed, the new number is 54 more than the original\", this means that \"10u%2Bt=10t%2Bu%2B54\"\r
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\n" ); document.write( "\n" ); document.write( "\"10u%2Bt=10t%2Bu%2B54\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"10%283t%29%2Bt=10t%2B3t%2B54\" Plug in \"u=3t\" (ie replace EVERY \"u\", without quotes, with \"3t\", without quotes)\r
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\n" ); document.write( "\n" ); document.write( "\"30t%2Bt=10t%2B3t%2B54\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"31t=10t%2B3t%2B54\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"31t=54%2B13t\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"31t-13t=54\" Subtract \"13t\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"18t=54\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"t=%2854%29%2F%2818%29\" Divide both sides by \"18\" to isolate \"t\".\r
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\n" ); document.write( "\n" ); document.write( "\"t=3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the tens digit is 3. Because we know that \"u=3t\", we can plug this into that equation to get \"u=3%283%29=9\". So the units digit is 9\r
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\n" ); document.write( "\n" ); document.write( "So the original number is 39. The new swapped number is 93. Notice how 93 is 54 more than 39 (ie 39+54 = 93)\r
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\n" ); document.write( "\n" ); document.write( "# 4\r
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\n" ); document.write( "\n" ); document.write( "Use the same basic strategy to solve this problem. Let me know if you still need help.
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