document.write( "Question 46555: i dont know how to do substitution method x=2y-3 4x+3y=32 \n" ); document.write( "
Algebra.Com's Answer #30849 by tutorcecilia(2152)\"\" \"About 
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x=2y-3 [Have one of the equations equal to either \"x\" or \"y\"]
\n" ); document.write( "4x+3y=32 [Substitute (x=2y-3) for \"x\" in the second equation]
\n" ); document.write( "4(2y-3)+3y=32 [Solve for y by simplifying]
\n" ); document.write( "8y-12+3y=32
\n" ); document.write( "11y-12=32
\n" ); document.write( "11y-12+12=32+12
\n" ); document.write( "11y/11=44/11
\n" ); document.write( "y=4
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\n" ); document.write( "x=2y-3 [Substitute (y=4) back into either equation and solve for \"x\"]
\n" ); document.write( "x=2(4)-3
\n" ); document.write( "x=5
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\n" ); document.write( "x=2y-3 and 4x+3y=32 [Plug (x=5) and (y=4) back into both equations]
\n" ); document.write( "(5)=2(4)-3 [Simplify]
\n" ); document.write( "5=5 [Checks out]
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\n" ); document.write( "4x+3y=32
\n" ); document.write( "4(5)+ 3(4)=32 [Simplify]
\n" ); document.write( "32=32 [Checks out]
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