document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448264>Question 448264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The graph of the equation below is a circle. What is the length of the radius of the circle?(x - 6)2 + (y + 5)2 = 152 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308469 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation is in the same form as that of a circle (x-h)^2 + (y-k)^2 = r^2, with r^2 = 152. This implies that r = sqrt(152). </SPAN>\n" );
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