document.write( "Question 448243: A mettallurgist needs to make 12.4lb of an alloy containing 50% gold. He is going to melt and combine on emetal that is 60% gold with another metal that is 40% gold. how much of each should he use? \n" ); document.write( "
Algebra.Com's Answer #308468 by dmhargrove(1)\"\" \"About 
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\n" ); document.write( "A metallurgist needs to make 12.4 lb of an alloy containing 50% gold.
\n" ); document.write( "He is going to melt and combine one metal that is 60% gold with another metal that is 40% gold. How much of each should he use?
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\n" ); document.write( "Equation:
\n" ); document.write( "gold + gold = gold
\n" ); document.write( "0.60x + 0.40(12.4-x) = 0.50*12.4
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "60x + 40*12.4 - 40x = 50*12.4
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\n" ); document.write( "20x = 10*12.4
\n" ); document.write( "---
\n" ); document.write( "x = 6.2 lb (amt. of 60% alloy needed)
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\n" ); document.write( "12.4-x = 6.2 lb (amt. of 40% alloy needed)
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