document.write( "Question 448243: A mettallurgist needs to make 12.4lb of an alloy containing 50% gold. He is going to melt and combine on emetal that is 60% gold with another metal that is 40% gold. how much of each should he use? \n" ); document.write( "
Algebra.Com's Answer #308462 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A metallurgist needs to make 12.4 lb of an alloy containing 50% gold. \n" ); document.write( "He is going to melt and combine one metal that is 60% gold with another metal that is 40% gold. How much of each should he use? \n" ); document.write( "------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "gold + gold = gold \n" ); document.write( "0.60x + 0.40(12.4-x) = 0.50*12.4 \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "60x + 40*12.4 - 40x = 50*12.4 \n" ); document.write( "------ \n" ); document.write( "20x = 10*12.4 \n" ); document.write( "--- \n" ); document.write( "x = 6.2 lb (amt. of 60% alloy needed) \n" ); document.write( "--- \n" ); document.write( "12.4-x = 6.2 lb (amt. of 40% alloy needed) \n" ); document.write( "=========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " |