document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=448109>Question 448109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I write this set?\r<BR>\n" );
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document.write( "Given: A= {1,2,3,4,5} B={2,4,6} C= {1,3,5}\r<BR>\n" );
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document.write( "AU(BUC)\r<BR>\n" );
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document.write( "U= union </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308429 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The U stands for <u>U</u>nion. This is where you simply combine two sets and erase any duplicates. \r<BR>\n" );
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document.write( "So in this case, B U C = {2,4,6,1,3,5}. Basically I just threw everything from B and C into one set.\r<BR>\n" );
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document.write( "So A U (B U C) = {1, 2, 3, 4, 5, 6}\r<BR>\n" );
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document.write( "Notes: sets B and C are subsets of A (ie everything in B is also in A. Same can be said for C). So A U B = A and A U C = A. So we can think of A U (B U C) as\r<BR>\n" );
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document.write( "A U (B U C) = (A U B) U C = A U C = A\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "A U (B U C) = A U (C U B) = (A U C) U B = A U B = A\r<BR>\n" );
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document.write( "Either way we get set A as an answer. </SPAN>\n" );
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