document.write( "Question 448034: suppose a fair coin is tossed twice. Find the probability of getting exactly one head is? \n" ); document.write( "
Algebra.Com's Answer #308367 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are two ways to figure this. Since there are only four possible outcomes for tossing two coins, you can simply enumerate them and count the successes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two successes out of four possiblities. Probablity is 1/2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or you can get fancy and use the formula for the probability of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Where \n" ); document.write( "\n" ); document.write( "Or for your problem:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |