document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46521>Question 46521</A>: <I><SPAN STYLE=\"word-break: break-all;\">     <BR>\n" );
document.write( "    Good evening, i have this problem about physic. i can not work out .Please would u work for me ?\r<BR>\n" );
document.write( "\n" );
document.write( "  Potential gravitational enery( defined as 'mass' mulitiplied by 'gravitational acceleration' by \"height\" - or mgh ) is one form of energy, and and kinetic energy ( defined as half the product of 'mass' mulitiply by 'velocity squared' - or mv2/2 ) is another. Assuming the conservation of energy ( and that there are no resisting forces ), from what height would a car have to fall to gain the kinetic energy it it would have when going at 60 kilometers per hour?\r<BR>\n" );
document.write( "\n" );
document.write( "  Please solve this problem for me.<BR>\n" );
document.write( "   Yours faithful student Emma Mode </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30833 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start by letting P = Potential gravitational energy = mgh.<BR>\n" );
document.write( "Let K = kinetic energy = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mv%5E2%2F2 ALIGN=MIDDLE  ALT=\"mv%5E2%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "To answer the question, you should set the potential gravitational energy, P equal to the kinetic energy, K\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mgh+=+mv%5E2%2F2 ALIGN=MIDDLE  ALT=\"mgh+=+mv%5E2%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify this by dividing both sides by m.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=gh+=+v%5E2%2F2 ALIGN=MIDDLE  ALT=\"gh+=+v%5E2%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve for h, the height.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+v%5E2%2F2g ALIGN=MIDDLE  ALT=\"h+=+v%5E2%2F2g\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "v is the velocity of the car (60 kmph) and you will need to convert this to metres per second.<BR>\n" );
document.write( "60 km = 60,000 metres<BR>\n" );
document.write( "1 hour = 3,600 secs\r<BR>\n" );
document.write( "\n" );
document.write( "So, 60 kmph = 60,000m per 3,600 secs. Simplifying this we get:<BR>\n" );
document.write( "v = 16.67 m/sec. Square this for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v%5E2 ALIGN=MIDDLE  ALT=\"v%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v%5E2+=+277.8 ALIGN=MIDDLE  ALT=\"v%5E2+=+277.8\"   DISABLED_style= \"max-width:90%; height:auto;\" > m^2/sec^2\r<BR>\n" );
document.write( "\n" );
document.write( "g (the gravitational constant of acceleration) is 0.98 m/sec^2<BR>\n" );
document.write( "Now you can find the height, h.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+277.8%2F2%280.98%29 ALIGN=MIDDLE  ALT=\"h+=+277.8%2F2%280.98%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+141.7 ALIGN=MIDDLE  ALT=\"h+=+141.7\"   DISABLED_style= \"max-width:90%; height:auto;\" > metres<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );