document.write( "Question 447967: I am helping a friend with Algebra. After 20 years, she has returned to school. she is stumped by this question that her ACC professor has given them:
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document.write( "9 2/9 - x for x = 6 2/3\r
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document.write( "It's been even longer since I've taken Algebra. Thanks for your assistance. \n" );
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Algebra.Com's Answer #308326 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! --> 9 2/9 - 6 2/3 \n" ); document.write( "= 83/9 - 20/3 \n" ); document.write( "= 83/9 - 60/9 \n" ); document.write( "= 23/9 \n" ); document.write( "= 2 5/9 \n" ); document.write( "---------- \n" ); document.write( "Avoid mixed numbers, if possible. \n" ); document.write( " |