document.write( "Question 447911: I need to solve x2(this is x squared)+2x-4=0
\n" ); document.write( "I tried to solve by adding 4 to both sides to get x squared +2x=4
\n" ); document.write( "Then I divided 2x by 2 and squaring to get 1
\n" ); document.write( "then I added one to both sides to get X squared +2x+1=5
\n" ); document.write( "Then I factored to get (x+1)squared=5
\n" ); document.write( "Then I took the square root of both sides to get x+1=sq root of 5
\n" ); document.write( "Then I subtracted one from both sides to get
\n" ); document.write( " x=-1+sq root of 5 and x=-1-sq root of 5\r
\n" ); document.write( "\n" ); document.write( "Is this correct? \n" ); document.write( "
Algebra.Com's Answer #308311 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi, Your Answer is correct, please review below
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document.write( " x^2+2x    + 1 = 5  |completing the square: x^2 + 2x = (x+1)^2 - 1
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document.write( " \"%28x%2B1%29%5E2-1+%2B1+=+5\"
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document.write( "    (x+1)^2 = 5
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document.write( "     x+1 = ± \"sqrt%285%29\"
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document.write( "      x = -1 ± \"sqrt%285%29\"
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