document.write( "Question 447946: The population of a city is growing exponentially. Initially the population was 43,000 while 7 years later the population was 79,700. Find\r
\n" ); document.write( "\n" ); document.write( "the population 4 years later (11 years from the beginning)\r
\n" ); document.write( "\n" ); document.write( "and the doubling time.
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Algebra.Com's Answer #308299 by stanbon(75887)\"\" \"About 
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The population of a city is growing exponentially. Initially the population was 43,000 while 7 years later the population was 79,700.
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\n" ); document.write( "Find the population 4 years later (11 years from the beginning)
\n" ); document.write( "and the doubling time.
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\n" ); document.write( "p = ab^t
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\n" ); document.write( "Solve for a and b:
\n" ); document.write( "---
\n" ); document.write( "Initial conditions (0,43000) so a = 43000
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\n" ); document.write( "p(7) = 43000*b^7 = 79,700
\n" ); document.write( "---
\n" ); document.write( "Divide by 43000 and solve for \"b\":
\n" ); document.write( "b^7 = 1.8535
\n" ); document.write( "---
\n" ); document.write( "b = 1.0922
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\n" ); document.write( "p(t) = 43000*(1.0922)^t
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\n" ); document.write( "Find the population 4 years later (11 years from the beginning)
\n" ); document.write( "p(11) = 43000*(1.0922)^11 = 113,395.39
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\n" ); document.write( "and the doubling time.
\n" ); document.write( "Solve 1.0922^t = 2
\n" ); document.write( "---
\n" ); document.write( "t*log(1.0922) = log(2)
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\n" ); document.write( "t = 7.86 years
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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