document.write( "Question 447883: two planes start from the same point and fly in opposite directions. the first plane is flying 50 mph slower than the second plane. in 2.5 hours the planes are 1400 miles apart. find the rate of each plane \n" ); document.write( "
Algebra.Com's Answer #308295 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Plane II x mph \n" ); document.write( "Plane I x-50 mph \n" ); document.write( ".. \n" ); document.write( "They are going away from each other. \n" ); document.write( "So add up their speed. \n" ); document.write( " \n" ); document.write( "combined speed = x+x-50 \n" ); document.write( "(2x-50) \n" ); document.write( "Time = 2.5 hours \n" ); document.write( "Distance = 1400 miles \n" ); document.write( "Distance = speed * time \n" ); document.write( "(2x-50)*2.5=1400 \n" ); document.write( "5x-125=1400 \n" ); document.write( "5x=1400+125 \n" ); document.write( "5x=1525 \n" ); document.write( "/5 \n" ); document.write( "x=305 mph Plane II \n" ); document.write( "Plane I 305+-50 =255 mph \n" ); document.write( " \n" ); document.write( " |