document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46512>Question 46512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x^2 + 12x = -5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30829 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x~2+12x+5=0 using [(-b+/-sqrtb~2-4ac)/2a] we get (-12+/-sqrt144-4*3*5)/6 or \r<BR>\n" );
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document.write( "(-12+/-sqrt144-60)/6 or (-12+/-sqrt84)/6 or (-12+/-2sqrt21)/6 or \r<BR>\n" );
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document.write( "(-6+/-sqrt21)/3 </SPAN>\n" );
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