document.write( "Question 447871: The area of a rectangle is 52.7 square meters. Its length is 2 meters more than its width. Find its dimensions.\r
\n" ); document.write( "\n" ); document.write( "I know it's more than 6 x 8 - and it's less than 7 x 9 - but how do you figure the fractions?\r
\n" ); document.write( "\n" ); document.write( "Thanks! \n" ); document.write( "
Algebra.Com's Answer #308262 by stanbon(75887)\"\" \"About 
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The area of a rectangle is 52.7 square meters. Its length is 2 meters more than its width. Find its dimensions.
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\n" ); document.write( "Let the width be \"w\".
\n" ); document.write( "Then length is \"w+2\".
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\n" ); document.write( "Area = (length)(width)
\n" ); document.write( "52.7 = (w+2)w
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\n" ); document.write( "w^2 + 2w - 52.7 = 0
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\n" ); document.write( "Quadratic Equation:
\n" ); document.write( "w = [-2 +- sqrt(4-4*1*-52.7)]/2
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\n" ); document.write( "w = [-2 +- sqrt(214)]/2
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\n" ); document.write( "w = [-2 +- 14.66]/2
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\n" ); document.write( "Positive solution:
\n" ); document.write( "w = [-2 + 14.66]/2 = 12.66/2 = 6.33 (width)
\n" ); document.write( "w+2 = 8.33 (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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