document.write( "Question 447846: How many liters of 60% solution of sulfuric acid should be added to 10 liters of a 30% solution of sulfuric acid to obtain a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #308254 by stanbon(75887)\"\" \"About 
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How many liters of 60% solution of sulfuric acid should be added to 10 liters of a 30% solution of sulfuric acid to obtain a 50% solution?
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\n" ); document.write( "acid + acid = acid
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\n" ); document.write( "0.60x + 0.30*10 = 0.50(x+10)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "60x + 30*10 = 50x + 50*10
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\n" ); document.write( "10x = 20*10
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\n" ); document.write( "x = 20 liters (amt. of 60% solution:
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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