document.write( "Question 447846: How many liters of 60% solution of sulfuric acid should be added to 10 liters of a 30% solution of sulfuric acid to obtain a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #308254 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of 60% solution of sulfuric acid should be added to 10 liters of a 30% solution of sulfuric acid to obtain a 50% solution? \n" ); document.write( "----- \n" ); document.write( "acid + acid = acid \n" ); document.write( "--- \n" ); document.write( "0.60x + 0.30*10 = 0.50(x+10) \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "60x + 30*10 = 50x + 50*10 \n" ); document.write( "--- \n" ); document.write( "10x = 20*10 \n" ); document.write( "--- \n" ); document.write( "x = 20 liters (amt. of 60% solution: \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========================== \n" ); document.write( " |