document.write( "Question 447573: (1.) The height of a triangle is 4 feet less than twice the base. If the area is 48 square feet, find the base and height.\r
\n" ); document.write( "\n" ); document.write( "(2.) The height of an object projected vertically is given by h=24t-16t^2. At what times will the object be on the ground? \n" ); document.write( "
Algebra.Com's Answer #308131 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
(1.) The height of a triangle is 4 feet less than twice the base. If the area is 48 square feet, find the base and height.
\n" ); document.write( "Since area of triangle = (1/2)*base*height
\n" ); document.write( "Let b = base
\n" ); document.write( "then
\n" ); document.write( "2b-4 = height
\n" ); document.write( "(1/2)b(2b-4) = 48
\n" ); document.write( "b(2b-4) = 96
\n" ); document.write( "2b^2-4b = 96
\n" ); document.write( "b^2-2b = 48
\n" ); document.write( "b^2-2b-48 = 0
\n" ); document.write( "(b-8)(b+6) = 0
\n" ); document.write( "b = {-6, 8}
\n" ); document.write( "throw out the negative solution leaving:
\n" ); document.write( "b = 8 feet (base)
\n" ); document.write( ".
\n" ); document.write( "height:
\n" ); document.write( "2b-4 = 2(8)-4 = 12 feet
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "(2.) The height of an object projected vertically is given by h=24t-16t^2. At what times will the object be on the ground?
\n" ); document.write( "set h to zero and solve for t:
\n" ); document.write( "0=24t-16t^2
\n" ); document.write( "0=3t-2t^2
\n" ); document.write( "0=t(3-2t)
\n" ); document.write( "t = {0, 3/2}
\n" ); document.write( "solution: 0 seconds and 1.5 seconds
\n" ); document.write( " \n" ); document.write( "
\n" );