document.write( "Question 447510: A mason can lay the bricks in a sidewalk in 14 hours. The mason's apprentice requires 22 hours to do the same job. After working together for 3 hours, the mason leaves for another job and the apprentice continues working. How long will it take the apprentice to complete the job?
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Algebra.Com's Answer #308089 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 3/14+3/22=33/154+21/154=54/154=27/77 completed, 50/77 left-- \n" ); document.write( "x/22=50/77 \n" ); document.write( "1100=77x \n" ); document.write( "14.28571=x \n" ); document.write( "It will take the apprentice 14.28571 hours to finish the job.. \n" ); document.write( " \n" ); document.write( " |