document.write( "Question 447466: (3-71)(3+7i)
\n" ); document.write( "(2-2i)(2+2i)
\n" ); document.write( "(7-10i)(7+10i)
\n" ); document.write( "(2+5i)(2-5i)
\n" ); document.write( "(4+3i)(1-i)
\n" ); document.write( "(5-7i)(1+2i)
\n" ); document.write( "(2-5i)(2-5i)
\n" ); document.write( "

Algebra.Com's Answer #308051 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "These can be done as one would use the FOIL method: Note: i^2 = -1
\n" ); document.write( "F First terms
\n" ); document.write( "O Outside terms
\n" ); document.write( "I Inside terms
\n" ); document.write( "L Last terms
\n" ); document.write( "(3-7i)(3+7i) = 9+49 = 58 | SUM of the outside terms and the inside terms = 0
\n" ); document.write( "(2-2i)(2+2i) = 4 + 4 = 8 | SUM of the outside terms and the inside terms = 0
\n" ); document.write( "(7-10i)(7+10i) = 49 + 100 = 149 | SUM of the outside terms and the inside terms = 0
\n" ); document.write( "(2+5i)(2-5i) = 4+ 25 = 29 | SUM of the outside terms and the inside terms = 0
\n" ); document.write( "(4+3i)(1-i) = 4 - i + 3 = 7 -i
\n" ); document.write( "(5-7i)(1+2i) = 5 +3i + 14 = 19 + 3i
\n" ); document.write( "(2-5i)(2-5i) = 4 -20i - 25 = 29 - 20i
\n" ); document.write( "Note: -5i*-5i = 25*-1 \n" ); document.write( "
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