document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=447452>Question 447452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hollow metal sphere has an internal radius of 20 cm and an external radius of 30 cm. Given that the density of the metal is 7.8 g/cm^3 (gramme per cm cube), find the weight of the sphere.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #308043 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=308043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> External volume - Internal volume)( * density = weight of sphere\r<BR>\n" );
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document.write( "4/3 pir^3= volume<BR>\n" );
document.write( "r1= 30<BR>\n" );
document.write( "r2=20<BR>\n" );
document.write( "4/3pi(r1^3-r2^3)= volume of shell<BR>\n" );
document.write( "4/3 * pi ( 27000-8000)<BR>\n" );
document.write( "4/3 * pi *19000<BR>\n" );
document.write( "== 79,587.01 cu.cm\r<BR>\n" );
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document.write( "....<BR>\n" );
document.write( "Density = 7.8gms/cu.cm<BR>\n" );
document.write( "79,587.01*7.8=620,778 gms\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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