document.write( "Question 447456: an express train travels 600 mi in the same amount of time it takes a freight to travel 360 mi. the rate of the express train is 20 mph faster than that of the freight train. find the rate of each train. \n" ); document.write( "
Algebra.Com's Answer #308040 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Freight train x ---360 miles \n" ); document.write( "Express x+20--- 600 miles \n" ); document.write( "360/x=600/(x+20) \n" ); document.write( "Cross multiply \n" ); document.write( "360(x+20 )=600* x \n" ); document.write( "360x+7200=600x \n" ); document.write( "600x-360 x=7200 \n" ); document.write( "240x=7200 \n" ); document.write( "/240 \n" ); document.write( "x=30 mph Freight train \n" ); document.write( "50 mph Express \r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |