document.write( "Question 447457: the president of a company travels 1800 mi by jet and 300 mi on a prop plane. the rate of the jet was four times the rate of the prop plane. the entire trip took a total of 5 h. find the rate of the jet plane. \n" ); document.write( "
Algebra.Com's Answer #308037 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! Let r = the rate of the jet plane \n" ); document.write( "Then r/4 = the rate of the prop plane \n" ); document.write( "Since time = distance/rate, we can write the following formula for the time of the trip: \n" ); document.write( "5 = 1800/r + 300/(r/4) \n" ); document.write( "5 = 1800/r + 1200/r \n" ); document.write( "Solve for r: \n" ); document.write( "(1800 + 1200)/r = 5 \n" ); document.write( "3000 = 5r \n" ); document.write( "r = 600 mph \n" ); document.write( "Therefore the rate of the jet is 600 mph \n" ); document.write( " |