document.write( "Question 447442: Solve: log5 (3x – 2) = 1 + log5 (x – 4) \n" ); document.write( "

Algebra.Com's Answer #308034 by stanbon(75887) $\"\"$ $\"About$

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log5 (3x – 2) = 1 + log5 (x – 4)
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\n" ); document.write( "log5(3x-2)-log5(x-4) = 1
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\n" ); document.write( "log5[(3x-2)/(x-4)] = 1
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\n" ); document.write( "(3x-2)/(x-4) = 5
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\n" ); document.write( "3x-2 = 5x-20
\n" ); document.write( "2x = 18
\n" ); document.write( "x = 9
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\n" ); document.write( "cheers,
\n" ); document.write( "stan H. \n" ); document.write( "

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