document.write( "Question 447412: Solve
\n" ); document.write( "2x^2-y^2=1
\n" ); document.write( "x+y=12
\n" ); document.write( "Please explain how to solve this in any form.
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Algebra.Com's Answer #308007 by mananth(16946)\"\" \"About 
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2x^2-y^2=1
\n" ); document.write( "x+y=12\r
\n" ); document.write( "\n" ); document.write( "x=12-y\r
\n" ); document.write( "\n" ); document.write( "2x^2-y^2=1
\n" ); document.write( "substitute x
\n" ); document.write( "2(12-y)^2-y^2=1
\n" ); document.write( "2(144-24y+y^2)-y^2=1
\n" ); document.write( "288-48y+2y^2-y^2=1
\n" ); document.write( "y^2-48y+288=1
\n" ); document.write( "y^2-48y+287=1
\n" ); document.write( "y^2-41y-7y+287=0
\n" ); document.write( "y(y-41)-7(y-41)=0
\n" ); document.write( "(y-41)(y-7)=0
\n" ); document.write( "y=41 OR 7
\n" ); document.write( "When y =41 x=-29 ( -29,41)
\n" ); document.write( "when y=7, x=5 (5,7)
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