document.write( "Question 447333: log 3 1 over 27 \n" ); document.write( "
Algebra.Com's Answer #307995 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! log 3 1 over 27 \n" ); document.write( ".. \n" ); document.write( "log3 1/27 \n" ); document.write( "what this problem is asking: what number x do you raise the base=3 to get a number=1/27\r \n" ); document.write( "\n" ); document.write( " 3^x=1/27=1/3^3=3^-3 \n" ); document.write( " x=-3\r \n" ); document.write( "\n" ); document.write( " In other terms, the logarithm of 1/27 to the base 3 is equal to -3 \n" ); document.write( " |