document.write( "Question 447333: log 3 1 over 27 \n" ); document.write( "
Algebra.Com's Answer #307995 by lwsshak3(11628)\"\" \"About 
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log 3 1 over 27
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\n" ); document.write( "log3 1/27
\n" ); document.write( "what this problem is asking: what number x do you raise the base=3 to get a number=1/27\r
\n" ); document.write( "\n" ); document.write( " 3^x=1/27=1/3^3=3^-3
\n" ); document.write( " x=-3\r
\n" ); document.write( "\n" ); document.write( " In other terms, the logarithm of 1/27 to the base 3 is equal to -3
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