document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=447357>Question 447357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of the following figure.  (geometry) 10th grade<BR>\n" );
document.write( "a picture of a kite with 7.5 cm on center line from top to bottom then 4.5 cm side<BR>\n" );
document.write( "to side thru the middle\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307981 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C300%2C0%2C10%2C0%2C10%2C%0D%0A%0D%0A%0D%0Aline%282%2C5%2C+4.25%2C1%29%2C%0D%0Aline%284.25%2C1%2C++6.5%2C5%29%2C%0D%0Aline%286.5%2C5%2C++4.25%2C8.5%29%2C%0D%0Aline%284.25%2C8.5%2C++2%2C5%29%2C%0D%0Aline%282%2C5%2C6.5%2C5%29%2C%0D%0Aline%284.25%2C1%2C4.25%2C8.5%29%0D%0A%0D%0A%0D%0A%29%0D%0A ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Assume the horizontal line has length 4.5 and the vertical line has length 7.5.\r<BR>\n" );
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document.write( "The kite can be broken into two triangles, each with base 4.5 and a different height. However, we know the sum of the heights is 7.5, so if we let b and 7.5-b be the heights, then\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE A = \frac{1}{2}(4.5)(b) + \frac{1}{2}(4.5)(7.5-b)\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE A = \frac{1}{2}(4.5)(7.5) = 16.875\">\r<BR>\n" );
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