document.write( "Question 447323: The length is 5 units more than the width. The perimeter is 9 times times the width. How do you find the length and the width of the rectangle described \n" ); document.write( "
Algebra.Com's Answer #307973 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "9W=2L+2W \n" ); document.write( "2L=7W \n" ); document.write( "L=W+5 \n" ); document.write( "9W=2(W+5)+2W \n" ); document.write( "7W=2W+10 \n" ); document.write( "5W=10 \n" ); document.write( "W=2 \n" ); document.write( "L=7 \n" ); document.write( "The length is 7 units, the width is 2 units.. \n" ); document.write( " |