document.write( "Question 447300: Two cyclists leave town at the same time on the same road going in the same direction. Cyclist A is going 6 miles per hour faster than cyclist B. After 8 hours cyclist A has traveled three times the distance as cyclist B. How fast is cyclist B traveling? \n" ); document.write( "
Algebra.Com's Answer #307964 by ankor@dixie-net.com(22740)\"\" \"About 
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Two cyclists leave town at the same time on the same road going in the same direction.
\n" ); document.write( " Cyclist A is going 6 miles per hour faster than cyclist B.
\n" ); document.write( " After 8 hours cyclist A has traveled three times the distance as cyclist B.
\n" ); document.write( " How fast is cyclist B traveling?
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of B cyclist
\n" ); document.write( "then
\n" ); document.write( "(s+6) = speed of A cyclist
\n" ); document.write( ":
\n" ); document.write( "Write a dist equation, Dist = time * speed
\n" ); document.write( "A's dist = 3 times B's dist
\n" ); document.write( "8(s+6) = 3(8s)
\n" ); document.write( "8s + 48 = 24s
\n" ); document.write( "48 = 24s - 8s
\n" ); document.write( "48 = 16s
\n" ); document.write( "s = 48/16
\n" ); document.write( "s = 3 mph is B's speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check by finding the actual dist each traveled
\n" ); document.write( "A: 9*8 = 72 mi
\n" ); document.write( "B: 3*8 = 24 mi \n" ); document.write( "
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