document.write( "Question 447227: Well, I have a math problem that say,\" Yoy have 180 feet of fence to make a rectangular pen. One side of the pen will be against a 200 foot wall, so it requires no fence. What are the dimensions of the rectangle with the maximum area?\" and i would like for you to help me on it. \n" ); document.write( "
Algebra.Com's Answer #307961 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! You have 180 feet of fence to make a rectangular pen. \n" ); document.write( " One side of the pen will be against a 200 foot wall, so it requires no fence. \n" ); document.write( " What are the dimensions of the rectangle with the maximum area?\" \n" ); document.write( ": \n" ); document.write( "The perimeter equation for a 3 sided pen \n" ); document.write( "L + 2W = 180 \n" ); document.write( "L = (180-2W) \n" ); document.write( ": \n" ); document.write( "The area equation: \n" ); document.write( "A = L*W \n" ); document.write( "replace L with (180-2W) \n" ); document.write( "A = W(180-2W) \n" ); document.write( "A = -2W^2 + 180W \n" ); document.write( "Max area occurs at the axis of symmetry, formula for that: x=-b/(2*a) \n" ); document.write( "In this equation \n" ); document.write( "W = \n" ); document.write( "W = \n" ); document.write( "W = +45 ft is the width for the max area \n" ); document.write( "Find the Length \n" ); document.write( "L = 180 - 2(45) \n" ); document.write( "L = 180 - 90 \n" ); document.write( "L = 90 ft is the length for max area \n" ); document.write( ": \n" ); document.write( "Actual area 45*90 = 4050 sq/ft\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |