document.write( "Question 447227: Well, I have a math problem that say,\" Yoy have 180 feet of fence to make a rectangular pen. One side of the pen will be against a 200 foot wall, so it requires no fence. What are the dimensions of the rectangle with the maximum area?\" and i would like for you to help me on it. \n" ); document.write( "
Algebra.Com's Answer #307961 by ankor@dixie-net.com(22740)\"\" \"About 
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You have 180 feet of fence to make a rectangular pen.
\n" ); document.write( " One side of the pen will be against a 200 foot wall, so it requires no fence.
\n" ); document.write( " What are the dimensions of the rectangle with the maximum area?\"
\n" ); document.write( ":
\n" ); document.write( "The perimeter equation for a 3 sided pen
\n" ); document.write( "L + 2W = 180
\n" ); document.write( "L = (180-2W)
\n" ); document.write( ":
\n" ); document.write( "The area equation:
\n" ); document.write( "A = L*W
\n" ); document.write( "replace L with (180-2W)
\n" ); document.write( "A = W(180-2W)
\n" ); document.write( "A = -2W^2 + 180W
\n" ); document.write( "Max area occurs at the axis of symmetry, formula for that: x=-b/(2*a)
\n" ); document.write( "In this equation
\n" ); document.write( "W = \"%28-180%29%2F%282%2A-2%29\"
\n" ); document.write( "W = \"%28-180%29%2F%28-4%29\"
\n" ); document.write( "W = +45 ft is the width for the max area
\n" ); document.write( "Find the Length
\n" ); document.write( "L = 180 - 2(45)
\n" ); document.write( "L = 180 - 90
\n" ); document.write( "L = 90 ft is the length for max area
\n" ); document.write( ":
\n" ); document.write( "Actual area 45*90 = 4050 sq/ft\r
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