document.write( "Question 447273: You invest $7200 in two accounts paying 8% and 10% annual interest. At the end of the year, the accounts earn the same interest. How much was invested at each rate?\r
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document.write( "I tried .08x + .10(7200-x) = 7200 and that did not work. Having a tough time coming up with the equation that will allow me to solve this word problem. Any help would be greatly appreciated. \n" );
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Algebra.Com's Answer #307942 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 8%----x \n" ); document.write( "10%----7200-x \n" ); document.write( "(you have equated the total interest to the total investment) \n" ); document.write( "Interest same \n" ); document.write( "0.08x=0.1(7200-x) \n" ); document.write( "0.08x=720-0.1x \n" ); document.write( "0.18x=820 \n" ); document.write( "x=720/0.18\r \n" ); document.write( "\n" ); document.write( "$4000 @ 8% \n" ); document.write( "Balance @10%\r \n" ); document.write( "\n" ); document.write( "CHECK \n" ); document.write( "0.08*4000=0.1*3200 \n" ); document.write( "320=320 \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |