document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46452>Question 46452</A>: <I><SPAN STYLE=\"word-break: break-all;\">  One day, the temperature at 2:00 A.M. was 43°F, and by 3:00 P.M. the temperature was 56°F.  What was the hourly rate of temperature change?\r<BR>\n" );
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document.write( "A)  3°F/h    B)  2°F/h    C)  0°F/h    D)  1°F/h<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30792 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 AM TO 3 PM IS 13 HOURS & THE TEMPERATURE INCREASED BY 13 DEGREES THUS THE RISE PER HOUR IS 13/13 OR 1 DEGREE/HOUR OR D)  </SPAN>\n" );
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