document.write( "Question 447163: Matt and Anna Killian are frequent fliers on fast-n-go airlines. They often fly between two cities that are a distance of 1680 miles apart. on one particular trip, they flew into the wind and the trip took 4 hours. The return trip with the wind behind them, only took about 3.5 hours. find the speed of the wind and the speed of the plane in still air \n" ); document.write( "
Algebra.Com's Answer #307916 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Remember Distance = Rate times Time\r
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\n" ); document.write( "\n" ); document.write( "Let represent the speed of the plane in still air. Let represent the speed of the wind. The rate of the plane against the wind is and the rate of the plane with the wind is .\r
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\n" ); document.write( "\n" ); document.write( "Divide the first equation by 4 and the second by 3.5:\r
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\n" ); document.write( "\n" ); document.write( "Add the two equations:\r
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\n" ); document.write( "\n" ); document.write( "and then substitute 450 back into either of the orginal equations to compute \r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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