document.write( "Question 447163: Matt and Anna Killian are frequent fliers on fast-n-go airlines. They often fly between two cities that are a distance of 1680 miles apart. on one particular trip, they flew into the wind and the trip took 4 hours. The return trip with the wind behind them, only took about 3.5 hours. find the speed of the wind and the speed of the plane in still air \n" ); document.write( "
Algebra.Com's Answer #307915 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 1680/4=420 \n" ); document.write( "1680/3.5=480 \n" ); document.write( "x+c=480 \n" ); document.write( "x-c=420 \n" ); document.write( "2x=900 \n" ); document.write( "x=450 \n" ); document.write( "The planes speed is 450 mph. The wind is 30 mph.. \n" ); document.write( " |