document.write( "Question 447113: find 2n^2 if n(n+3)=4 \n" ); document.write( "

Algebra.Com's Answer #307897 by htmentor(1343) $\"\"$ $\"About$

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n(n+3)=4
\n" ); document.write( "n^2 + 3n = 4
\n" ); document.write( "n^2 + 3n - 4 = 0
\n" ); document.write( "Solve for n using the quadratic formula:
\n" ); document.write( " $\"n+=+%28-3+%2B-+sqrt%289+%2B+16%29%29%2F2\"$
\n" ); document.write( "This gives n = 1,-4
\n" ); document.write( "So 2n^2 = 2 or 32 \n" ); document.write( "

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