document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=447149>Question 447149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What value of x will make the equation 3(x + 15) - 6x = -6(x - 3) true? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307876 by </B><A HREF=/tutors/aboutme.mpl?userid=Leaf+W.><B>Leaf W.(135)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Leaf+W.><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Leaf+W.><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x!<BR>\n" );
document.write( "3(x + 15) - 6x = -6(x - 3)<BR>\n" );
document.write( "Distribute the 3 into the x and 15 and the -6 into the x and -3: 3x + 45 - 6x = -6x + 18<BR>\n" );
document.write( "Combine like terms: -3x + 45 = -6x + 18<BR>\n" );
document.write( "Add 6x to both sides: 3x + 45 = 18<BR>\n" );
document.write( "Subtract 45 from both sides: 3x = -27<BR>\n" );
document.write( "Divide both sides by 3 to isolate the x: x = -9<BR>\n" );
document.write( "==> Therefore, x = -9 </SPAN>\n" );
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