document.write( "Question 447012: I have some 40% solution of alcohol and some pure alcohol. How much of each must I mix to get 60 ounces of a 50% solution? \n" ); document.write( "
Algebra.Com's Answer #307827 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! .4x+1(60-x)=30 \n" ); document.write( ".4x+60-x=30 \n" ); document.write( "60-.6x=30 \n" ); document.write( "30=.6x \n" ); document.write( "30/.6=x=50 \n" ); document.write( "You need 50 ozs. of 40% solution and 10 ozs. of 100% solution to get 60 ozs. of 50% solution.. \n" ); document.write( " |