document.write( "Question 447052: The rim of a basketball hoop is 10 feet above the ground. The free-throw line is 15 feet from the rim of the basket. If the eyes of a basketball player are 6 feet above the ground, what is the angle of elevation of the player's line of sight when shooting a free throw to the rim of the basket?\r
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document.write( "please show all work so i can understand better \n" );
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Algebra.Com's Answer #307800 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The rim of a basketball hoop is 10 feet above the ground. The free-throw line is 15 feet from the rim of the basket. If the eyes of a basketball player are 6 feet above the ground, what is the angle of elevation of the player's line of sight when shooting a free throw to the rim of the basket? \n" ); document.write( "------------------------------------------------- \n" ); document.write( "Draw the picture. \n" ); document.write( "You have a right triangle with base = 15 ft \n" ); document.write( "and height = (10-6) = 4 ft \n" ); document.write( "---- \n" ); document.write( "The angle of elevation is tan^-1(4/15) = 14.93 degrees. \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |