document.write( "Question 447052: The rim of a basketball hoop is 10 feet above the ground. The free-throw line is 15 feet from the rim of the basket. If the eyes of a basketball player are 6 feet above the ground, what is the angle of elevation of the player's line of sight when shooting a free throw to the rim of the basket?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "please show all work so i can understand better
\n" ); document.write( "

Algebra.Com's Answer #307800 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The rim of a basketball hoop is 10 feet above the ground. The free-throw line is 15 feet from the rim of the basket. If the eyes of a basketball player are 6 feet above the ground, what is the angle of elevation of the player's line of sight when shooting a free throw to the rim of the basket?
\n" ); document.write( "-------------------------------------------------
\n" ); document.write( "Draw the picture.
\n" ); document.write( "You have a right triangle with base = 15 ft
\n" ); document.write( "and height = (10-6) = 4 ft
\n" ); document.write( "----
\n" ); document.write( "The angle of elevation is tan^-1(4/15) = 14.93 degrees.
\n" ); document.write( "==================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );