document.write( "Question 447019: Hi, I'm not sure which section to be asking these questions under, but i would really appreciate the help! :)\r
\n" ); document.write( "\n" ); document.write( "Find A and B such that: 2x/(2x-3)(x+5)=A/2x-3+B/x+5
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Algebra.Com's Answer #307795 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "2x/(2x-3)(x+5)=A/2x-3 + B/x+5\r
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\n" ); document.write( "\n" ); document.write( "A/2x-3 + B/x+5 = [ A(x+5) + B(2X-3) ]/(2X-3)(X+5)\r
\n" ); document.write( "\n" ); document.write( "= [ X(A+2B) + 5A-3B ]/ (2X-3)(X+5)\r
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\n" ); document.write( "\n" ); document.write( "now, compare both numerator and compare value of X and constant values..\r
\n" ); document.write( "\n" ); document.write( "A+2B = 2 , 5A-3B = 0\r
\n" ); document.write( "\n" ); document.write( "solving these equations, A = 6/ 13 , B = 10/13 \r
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