document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=447019>Question 447019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I'm not sure which section to be asking these questions under, but i would really appreciate the help! :)\r<BR>\n" );
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document.write( "Find A and B such that: 2x/(2x-3)(x+5)=A/2x-3+B/x+5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #307793 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=307793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find A and B such that: 2x/(2x-3)(x+5)=A/2x-3+B/x+5<BR>\n" );
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document.write( "2x/(2x-3)(x+5) = A/(2x-3)+ B/(x+5)<BR>\n" );
document.write( "A(x+5) + B(2x-3) = 2x<BR>\n" );
document.write( "Ax + 2Bx + 5A - 3B = 2x<BR>\n" );
document.write( "A + 2B = 2<BR>\n" );
document.write( "5A - 3B = 0<BR>\n" );
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document.write( "A = 6/13<BR>\n" );
document.write( "B = 10/13\r<BR>\n" );
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document.write( " </SPAN>\n" );
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